I think the horizontal aymptope for that function is y=1. I think I understand how to get horizontal asymptopes when given a function. I don't know what f'(x)= 0 when x<-1 or x>1 means. Could somebody please explain this to me?
I also have trouble drawing a graph when the funcion is given.
For example:
Sketch the graph of a positive continuous function y = f(x) having all of these properties:
absolute maximum point at (0, 4);
f’(x) > 0 if x= (-infinity, 0) U (2, + infinity)
f’(x) < 0 if x= (0,2)
f’’(x) < 0 if x= (-2,2) U (2,infinty)
f’’(x) > 0 if x= (-infinty,-2)
lim (as x approaches – infinty) f(x)=0
lim (as x approaches + infinty) F(x) = 3
This is what I get from the above question:
The absolute maximum occurs at (0,4).
Two horizontal asympopes ath y=0 and y=3.
The function is increasing from -infinty to 0 and from 2 to + infinity.
The function is decreasing from 0 to 2.
The function is concave down from -2 to 2 and from 2 to positive infinity.
The function is concave up from - infinty to -2.
I am having trouble drawing this and would appreciate it if somebody could post a solution for me to verify if i am drwing it correctly.