Conan_Barbarian
New member
- Joined
- Feb 1, 2012
- Messages
- 1
The problem goes as follows...
There is a girl 15' away from a basketball goal who is 5'6'' tall and will release the ball straight up at a height of 6'6''.
There is also a girl 2' in front of the girl shooting who is 6' tall and who can reach into the air to block the shot at a height of 7'6''.
The rim for the basketball hoop in 18'' in diameter and sticks out 6'' from the basketball post which is at a height of 10'. (So total going from the post to the end of the rim it is 2' because it sticks out 6'')(also rim sticks out at a height of 10')
The ceiling is 30' high and the ball must not hit it to go in.
The ball is 12'' in diameter.
Find a quadratic equation the defines height h(d) as a function of the horizontal distance from the basketball post (d). so basically height=something(d)
the ball must go directly through the center of the rim and not hit the ceiling, backboard, or girl trying to block the shot. You will graph the CENTER of the ball so you must take into account that there is 6'' on either side of the function on a graph that could hit certain things. ALSO the origin of the graph is basically right up against the post and on the ground (no height no distance), so the function will have to be transformed for the equation to work.
I have been working on this forever!!! and still can't get it and would appreciate some help. All you math lovers have fun with this one!
There is a girl 15' away from a basketball goal who is 5'6'' tall and will release the ball straight up at a height of 6'6''.
There is also a girl 2' in front of the girl shooting who is 6' tall and who can reach into the air to block the shot at a height of 7'6''.
The rim for the basketball hoop in 18'' in diameter and sticks out 6'' from the basketball post which is at a height of 10'. (So total going from the post to the end of the rim it is 2' because it sticks out 6'')(also rim sticks out at a height of 10')
The ceiling is 30' high and the ball must not hit it to go in.
The ball is 12'' in diameter.
Find a quadratic equation the defines height h(d) as a function of the horizontal distance from the basketball post (d). so basically height=something(d)
the ball must go directly through the center of the rim and not hit the ceiling, backboard, or girl trying to block the shot. You will graph the CENTER of the ball so you must take into account that there is 6'' on either side of the function on a graph that could hit certain things. ALSO the origin of the graph is basically right up against the post and on the ground (no height no distance), so the function will have to be transformed for the equation to work.
I have been working on this forever!!! and still can't get it and would appreciate some help. All you math lovers have fun with this one!