Homework

[kittu1000]

At student dance 300 student usually attend and ticket price is $8.
For every $1 increased the # of students attending drops by 30.
What ticket price will maximize reveune ?

 

[tkhunny]

What's your plan for a solution?

300 * 8 = ??
270 * 9 = ??
240 * 10 = ??

Get the picture?

 

[lookagain]

At student dance 300 student usually attend and ticket price is $8.
For every $1 increased the # of students attending drops by 30.
What ticket price will maximize reveune ?

This question is the type that is geared toward a college algebra course or a
beginning applied calculus course, as it is about maximizing revenue.

For instance, in general, the amount of money increased need not be an
integer amount, so a listing method by tkhunny may not catch it.


Let 8 + x = the ticket price that maximizes

Revenue = (300 - 30x)(8 + 1x)

You might get it in the form of \(\displaystyle ax^2 + bx + c\) and use\(\displaystyle x = \frac{-b}{2a}.\)

Or, you could take the derivative of the revenue function, and then set it equal to 0 and solve.

 

[tkhunny]

This question is the type that is geared toward a college algebra course or a
beginning applied calculus course, as it is about maximizing revenue.

Maybe. If you really need a howitzer when a pea-shooter will do.

 

[lookagain]

This question is the type that is geared toward a college algebra course or a
beginning applied calculus course, as it is about maximizing revenue.

Maybe. If you really need a howitzer when a pea-shooter will do.

This question is not asked in a class based in arithmetic. The student must have typed this
problem in the wrong forum, as "maximizing revenue" is not in an arithmetic or typical elementary
algebra course. This problem would likely have come from the one of the suggested courses I stated.

Here's an example that listing (by whole numbers) doesn't get a solution:

At a student dance, 75 students usually attend and the ticket price is $8.
For every $1 increase, the # of students attending drops by 15.
What ticket price will maximize revenue ?

It turns out that $9.50 is the ticket price that maximizes the revenue.

 

[tkhunny]

I've seen 4th graders bring home such problems. It is not always easy to tell what level solution is required unless there is additional information. One must determine what section is currently under investigation.