Homework help Radical Expressions and Equations

[aschauer]

Stuck on these last three problems help would be greatly appreciated!!
Decide whether or not the ordered pair is a solution of the system.

(1, -3)
2x + y = -1
3x + 2y = -3

Decide whether or not the ordered pair is a solution of the system.


(12, 6)
y = 1
2
x
2x + y = 18


Solve using the substitution method.

x + y = -4
y = -3x + 2

 

[Aladdin]

Decide whether or not the ordered pair is a solution of the system.

(1, -3)
2x + y = -1
3x + 2y = -3

Replace the given values , for example :

2(1) +(-3) = -1
2 -3 +1 = 0 . . . Yes,it's a solution for the first equation. Let's check the second equation

3(1) +2(-3) +3 =
3 -6 +3 = 0 . . . True , So the ordered pair is a solution of the system.

Decide whether or not the ordered pair is a solution of the system.


Solve using the substitution method.

x + y = -4
y = -3x + 2[/quote]

Check this website,please.
http://www.purplemath.com/modules/systlin4.htm


Many smiles,

 

[mmm4444bot]

Decide whether or not the ordered pair is a solution of the system.

(12, 6)
y = 1
2
x
2x + y = 18

Looks like you have some typographical errors to correct, in the system above.

 

[garf]

FOR PROBLEM 1:
THE SOLUTION YOU PROPOSED IS RIGHT
FOR PROBLEM 2:
THERE IS A TYPO AND IT IS NOT CLEAR WHICH IS THE SYSTEM OF EQUATIONS
FOR PROBLEM 3:
THIS SYSTEM CAN BE EASILY ADDRESSED BY SUBSTITUTION, BECAUSE YOU ONLY HAVE TO ISOLATE ONE OF THE VARIABLES ON FIRST EQUATION AND THEN SUBSITUTE IT ON YOUR SECOND EQUATION. THE SOLUTION I GOT IS (3,-7)
GARF

 

[Mrspi]

Garf, please don't type in "all caps".....it hurts my ears! No need for shouting here.

 

[Aladdin]

FOR PROBLEM 1:
THE SOLUTION YOU PROPOSED IS RIGHT

Who proposed ?

In the first post,there's no any attempt to solve the solution.

 

[Denis]

Who proposed ?

Soroban proposed to Mrspi