Hmm...Transformation help

K.ourt

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Jul 20, 2005
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Ok, thats the question, and I'm having trouble with finding out how much it is stretched by. I drew the reflected function in in pencil. But I seem to be stuck on the stretching part. Someone told me it was 2, but I want to know how to do it, not just take someones word for it. Now, I know (or rather, think I know) that it is reflected across the y-axis, that it is horizontally shifted two to the right, and that it is vertically translated up one unit. So I have the equation being: a(squareroot of x-2)+1, a=stretch factor. But mapping my points only works for A.

So! How do I figure out the stretch factor? I know its 2 by 1, so would that make it 1/2 or 2? Uhm..yea Im lost here. Heh. OH, and am I doing anything right? I would ask my teacher, but Im not at school for Mon. or Tues. cuz of a field trip..
 
As you said, the parabola (if it was whole) faces to the left, so, along with all your other observations, its equation is \(\displaystyle \mbox{y = a\sqrt{-(x - 2)} + 1}\). Agreed?

By substituting one of the known points (A', B' or C') into the equation you can solve for a (it is irrational).
 
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