History of Math: Let z/pq = 1/pr + 1/qr, where r = p + q/z.

[Nan]

Let z/pq = 1/pr + 1/qr, where r = p + q/z.

Show that the equations hold. Hint: Substitute the second equation for r in the first equation and show the first equation reduces to an identity. How do I do that?

 

[Deleted member 4993]

Let z/(pq) = 1/(pr) + 1/(qr), where r = (p + q)/z.

Show that the equations hold. Hint: Substitute the second equation for r in the first equation and show the first equation reduces to an identity. How do I do that?

z/(p*q) = 1/(p*r) + 1/(q*r) = 1/[p*(p + q)/z] + 1/[q*(p + q)/z]

continue.....