What is your final solution? If you share your work/thoughts, we can guide you.[math]\int\limits_{0}^{\frac{U}{P}}\frac{e^{uvP}}{(v+1)^2} dv + \int\limits_{\frac{U}{P}}^{\infty}\frac{e^{uU}}{(v+1)^2} dv[/math]
Please share your work - detailed intermediate work.this is my final solution:
[math]Pue^{-Pu}\mathrm{Ei}(uU+Pu)-Pue^{-Pu}\mathrm{Ei}(Pu)+1[/math]
Please make sure to check that this integral is in the correct form. It doesn't look anything like your integrated result.[math]\int\limits_{\frac{U}{P}}^{\infty}\frac{e^{uU}}{(v+1)^2} dv[/math]
Thanks Dan for the reply. But this is correct form that has to be integrated.Please make sure to check that this integral is in the correct form. It doesn't look anything like your integrated result.
-Dan
What are those indefinite integrals? Please post the Expressions you had derived. Did you differentiate those to check whether you got back your original "integrands"?Hi! Yes I have calculated the indefinite integrals. I am not sure the final answer is correct as I am not getting desired output when I am plotting.
Why not? When you are not sure of accuracy of your integration - you can check it yourself by differentiating the integrated expression.I have not differentiated to check back.
Okay, I have run through this again (much more carefully) and I'm getting your result. You did it correctly.I have checked after you said and it is not coming same. Can you please share your solution.