Problem is this. Solve the initial value problem written below. dy/dt = y(k^2-y^3), y(0)=y0
M muhexp New member Joined May 4, 2020 Messages 1 May 4, 2020 #1 Problem is this. Solve the initial value problem written below. dy/dt = y(k^2-y^3), y(0)=y0
D Deleted member 4993 Guest May 4, 2020 #2 muhexp said: Problem is this. Solve the initial value problem written below. dy/dt = y(k^2-y^3), y(0)=y0 Click to expand... If I were to this problem, I would separate the variables: dy/dt = y(k^2-y^3) dy/[ y(k^2-y^3)] = dt then use partial fractions on the left-hand-side and continue...... Please show us what you have tried and exactly where you are stuck. Please follow the rules of posting in this forum, as enunciated at: https://www.freemathhelp.com/forum/threads/read-before-posting.109846/#post-486520 Please share your work/thoughts about this assignment.
muhexp said: Problem is this. Solve the initial value problem written below. dy/dt = y(k^2-y^3), y(0)=y0 Click to expand... If I were to this problem, I would separate the variables: dy/dt = y(k^2-y^3) dy/[ y(k^2-y^3)] = dt then use partial fractions on the left-hand-side and continue...... Please show us what you have tried and exactly where you are stuck. Please follow the rules of posting in this forum, as enunciated at: https://www.freemathhelp.com/forum/threads/read-before-posting.109846/#post-486520 Please share your work/thoughts about this assignment.
