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Morgan123

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Oct 31, 2012
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An isosceles triangle has a vertex angle of 36 degrees. If the congruent sides are 22 in long what is the area of the triangle?
 
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An isosceles triangle has a vertex angle of 36 degrees. If the congruent sides are 22 in long what is the area of the triangle?

Hello. I supposed it's standard to refer to the angle opposite the non-congruent side as the "vertex angle" in an isosceles triange, yet every triangle has three vertices.

Why are you posting this exercise on the Finance Board? Is some business-math instructor trying to test your knowledge of triangle-geometry and/or trigonometry?

Let's start with what you already know or have tried. Did you get stuck somewhere?

Hints: Look at this page for "isosceles triangle"

Your "top" angle is 36 degrees

Bisecting the "top" angle results in mirror-image right-triangles with hypotenuse 22

elementary right-triangle trigonometry solves for half of the base

same approach (or Pythagorean Theorem) gives the triangle's height

multiply them together because the area of a triangle is 1/2*base*height

Questions?
 
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