Help!

marchbaby68

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Oct 18, 2009
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I am new to algebra and need some help. I have this problem but do not even know where to begin to solve it. Any help would be greatly appreciated.

f varies jointly as h and the square of q, and f = 36 when q = 2 and h = 3. Find k.
 


You can google keywords: joint variation

There are many examples and explanations available.

Are you familiar with "direct variation"?

Joint variation is simply direct variation with extra variables.

For example, if y varies directly with x, then their relation is:

y = k * x

where k is some arbitrary constant.

The following equations are examples of direct variation between x and y.

y = 5x

y = (1/2)x

y = Pi * x

With joint variation, there are two (or more) variables that vary directly with y.

y = k * x * z

Here, we say that y varies jointly with x and z.

Again, k represents an arbitrary constant.

The following equations are examples of joint variation.

y = 5 x z

y = (1/2) x z

y = 444 x z

Of course, neither x nor z are required to be to the first power.

If y varies jointly as x and the square root of z, then we have the following.

y = k * x * sqrt(z)

If we're told that y = 616 when x = 7 and z = 16, then we find the value of k by subsituting all of the given values into the joint-variation equation, followed by solving the resulting equation for k.

616 = k * 7 * sqrt(16)

k = 22

Does this help?

If you need more assistance with this exercise, please show us what you've been able to do so far, or explain why you think you're stuck.

Cheers,

~ Mark

 
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