Help!

mathman1

New member
Joined
Feb 1, 2006
Messages
6
f(x) =
nqppn8.jpg
-
nqppud.jpg
+
nqppxi.jpg
, find f'(x)

I am getting -
nqpqgo.jpg
-
nqpqma.jpg
-
nqpqoj.jpg


I am not sure if this is right or not. I wo uld appreciate any feedback. Thanks.
 
Started out good, but...
d(-3/x) = d(-3x^-1) = +3/x²
d(2/x^5) d(2*x^-5) = -2*5x^-6
 
Top