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help
- Thread starter im_fed_up
- Start date
ChaoticLlama
Junior Member
- Joined
- Dec 11, 2004
- Messages
- 199
in general, the equation of the line is
y = mx + b
where y is the ordinate, x is the abscissa, m is the slope, and b is the y intercept.
Solving this equation is a matter of plugging in numbers, and solving for b.
y = mx + b
where y is the ordinate, x is the abscissa, m is the slope, and b is the y intercept.
Solving this equation is a matter of plugging in numbers, and solving for b.
im_fed_up said:Directions: find the general form of the equation of the line that passes through the given pint and has the indicated slope.
Point: (0,-2)
Slope: m=3
help me please?
I am not sure what you mean by "general form of the equation of the line".....perhaps
Ax + By = C
I would start with the slope-intercept form,
y = mx + b
m is the slope.....you're given that!
b is the y-intercept....and look at your given point (0, -2). It's on the y-axis, isn't it? Do you now know where your line crosses the y-axis?
Write the equation in slope-intercept form, and then "rearrange" the equation into the form desired as an answer. If you want it in the form Ax + By = C, you'll need to get the x and y terms on the same side of the equals sign, and make sure that the coefficient of x is positive.
I hope this helps you.