HELP!!!!!!!!!!!

[nick29]

Morgan and Thomas left Seattle at three in the afternoon, traveling in opposite directions. At six p.m., they were one hundred eighty-nine kilometers apart. If Thomas' rate of speed is two times that of Morgan's, what is Morgan's speed?

 

[Denis]

Morgan and Thomas left Seattle at three in the afternoon, traveling in opposite directions. At six p.m., they were one hundred eighty-nine kilometers apart. If Thomas' rate of speed is two times that of Morgan's, what is Morgan's speed?

m = Morgan's speed; then Thomas' speed = 2m

time = 3, distance = 189

speed = distance divided by time

OK?

 

[nick29]

word problems again!!!!

Megan left Seattle at 4:34 p.m. and traveled at a rate of thirty-one kph more than two times the speed of Isaac, who left at the same time but in the opposite direction. By the time it was 5:47 p.m., they were 133 kilometers apart. What was Megan's speed?

 

[stapel]

Please do not multi-post, or post new questions as replies to old threads. Thank you.

Eliz.

 

[Denis]

Re: word problems again!!!!

Megan left Seattle at 4:34 p.m. and traveled at a rate of thirty-one kph more than two times the speed of Isaac, who left at the same time but in the opposite direction. By the time it was 5:47 p.m., they were 133 kilometers apart. What was Megan's speed?

Again?!
Isaac = x kph; then Megan = 2x + 31

Finish it.

 

[Gene]

(3x+31)*73/60=133
x=26.1
m=83.2
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Gene