Help with this simplification process. ALGEBRA HELP.

[WTFDOUGLAS]

Hi forum. I'm new here. I'm taking calculus I right now, but it seems my foundation in pre-calculus isn't as strong as it should be. Nonetheless, I have a B average right now.

This question is a calculus problem, but I can do the calculus part. The algebra part is killing me. Could someone break this simplification process into smaller steps for me? I do not see how this is achieved.

\(\displaystyle g'(x)\, =\, x\left(\dfrac{1}{2}\right)(x\, +\, 5)^{-1/2}\, +\, (x\, +\, 5)^{1/2}\, =\, \dfrac{1}{2}(x\, +\, 5)^{-1/2}\left(x\, +\, 2(x\, +\, 5)\right)\, =\, \dfrac{3x\, +\, 10}{2\sqrt{x\, +\, 5\,}}\)

Any help would be greatly appreciated.

 

[Deleted member 4993]

Hi forum. I'm new here. I'm taking calculus I right now, but it seems my foundation in pre-calculus isn't as strong as it should be. Nonetheless, I have a B average right now.

This question is a calculus problem, but I can do the calculus part. The algebra part is killing me. Could someone break this simplification process into smaller steps for me? I do not see how this is achieved.

\(\displaystyle g'(x)\, =\, x\left(\dfrac{1}{2}\right)(x\, +\, 5)^{-1/2}\, +\, (x\, +\, 5)^{1/2}\, =\, \dfrac{1}{2}(x\, +\, 5)^{-1/2}\left(x\, +\, 2(x\, +\, 5)\right)\, =\, \dfrac{3x\, +\, 10}{2\sqrt{x\, +\, 5\,}}\)

Any help would be greatly appreciated.

\(\displaystyle \frac{1}{2}(x+5)^{-\frac{1}{2}}[x+2*(x+5)]\) = ?

can you simplify:

x + 2 * (x + 5) = ?

Do you know:

\(\displaystyle (x+5)^{-\frac{1}{2}} \ = \ \dfrac{1}{\sqrt{x+5}}\)