Help with rules of exponents

[cjusten]

I am normally pretty good with this lesson but I have a question that I cant figure out. It goes (2^(1/2)-2^(-1/2))^-1.

I already put this into Wolfram Alpha and it gave me an answer of square root of 2. That answer seems like it could be right, but the way they had their steps made it really confusing.
Thanks in advance.

 

[Deleted member 4993]

I am normally pretty good with this lesson but I have a question that I cant figure out. It goes (2^(1/2)-2^(-1/2)0^-1.

I already put this into Wolfram Alpha and it gave me an answer of square root of 2. That answer seems like it could be right, but the way they had their steps made it really confusing.
Thanks in advance.

There is no question to be answered!!

Moreover, (2^(1/2)-2^(-1/2)0^-1 does not make sense.

Especially that 0 in there!!

Please read your post after posting and make sure it is correct.

 

[cjusten]

truly sorry. I edited now to right thing.

 

[Deleted member 4993]

I am normally pretty good with this lesson but I have a question that I cant figure out. It goes (2^(1/2)-2^(-1/2))^-1.

I already put this into Wolfram Alpha and it gave me an answer of square root of 2. That answer seems like it could be right, but the way they had their steps made it really confusing.
Thanks in advance.

\(\displaystyle \displaystyle {\sqrt{2}-\frac{1}{\sqrt{2}}}\)

\(\displaystyle = \displaystyle{\sqrt{2} * \frac{\sqrt{2}}{\sqrt{2}} \ - \ \frac{1}{\sqrt{2}}}\)

\(\displaystyle = \displaystyle{\frac{\sqrt{2}*\sqrt{2}}{\sqrt{2}}\ - \ \frac{1}{\sqrt{2}}}\)


now continue...

 

[Deleted member 4993]

[2^(1/2) - 2^(-1/2)]^-1

= [(sqrt(2) - 1/sqrt(2)]^-1

= 1 / [(sqrt(2) - 1/sqrt(2)]

......dans le coin, pour 22 minutes et 30 secondes :twisted:

আমি কোণায় যাচ্ছি না

I left the final []^-1 for the OP to discover - since s/he already knew the answer!!