Help with problem

[moosie2323]

Here is the problem:

Find the standard form of the equation of the line through (-1,1) that is perpendicular to the line 6x-y=11

What are the steps that i would take to solve this problem?

 

[galactus]

Solve the given equation for y. Then, the coefficient of x is the slope. The slope of the required perp. line will be the negative reciprocal of that line.

Using y=mx+b, sub in x, y, and m and solve for b. You're done.

 

[pka]

To write the equation of a line one needs a point and a slope.
You have the point.
Now you need a slope.
Two lines are perpendicular lines (neither is vertical) have slopes which multiply to -1.
Thus the slope you want is \(\displaystyle \frac {-1}{6}\).