Integrate by parts: (xe^x)/((x+1)^2)? Is there a trick to know what to pick for u and Dv
S Scoberman New member Joined Oct 28, 2007 Messages 3 Oct 28, 2007 #1 Integrate by parts: (xe^x)/((x+1)^2)? Is there a trick to know what to pick for u and Dv
stapel Super Moderator Staff member Joined Feb 4, 2004 Messages 16,582 Oct 28, 2007 #2 Scoberman said: Is there a trick to know what to pick for u and Dv Click to expand... Not really. You try things one way. If that works, you're done. If not, then you try things another way. :wink: Eliz.
Scoberman said: Is there a trick to know what to pick for u and Dv Click to expand... Not really. You try things one way. If that works, you're done. If not, then you try things another way. :wink: Eliz.
G galactus Super Moderator Staff member Joined Sep 28, 2005 Messages 7,216 Oct 28, 2007 #3 Yes, there is a trick..........practice and doing lots of them. :lol: With this one: \(\displaystyle \L\\u=xe^{x}, \;\ dv=\frac{1}{(x+1)^{2}}dx, \;\ du=(x+1)e^{x}dx, \;\ v=\frac{-1}{x+1}\) Now, can you put it together?.
Yes, there is a trick..........practice and doing lots of them. :lol: With this one: \(\displaystyle \L\\u=xe^{x}, \;\ dv=\frac{1}{(x+1)^{2}}dx, \;\ du=(x+1)e^{x}dx, \;\ v=\frac{-1}{x+1}\) Now, can you put it together?.
