First step: factor. Then find the zeroes. The zeroes (there will be two of them) will split the number line (negative infinity to positive infinity) into three intervals.
You need to find the interval(s) on which x<sup>2</sup> - 3x + 2 is positive. So either pick one value inside each interval, plugging the values into "x<sup>2</sup> - 3x + 2" and checking the sign (plus or minus) on the answer, or else just think about the graph of a positive quadratic. Where is that sort of quadratic above the x-axis (positive) and below the x-axis (negative)? You want the interval(s) where the graph is above the x-axis.
Oh, and since this is an "or equal to" inequality, you'll need to include the zeroes in the solution as well.
If you get stuck, please reply showing how far you have gotten. Thank you.
Eliz.