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Help with equations of parabolas
- Thread starter sarahilc
- Start date
sarahilc said:I'm having trouble with converting equations from vertex and factored form into standard... I just don't really get it.
How would I begin to rewrite this in standard form?:
y=(x-1)(5x+2)
I suppose much depends on the definition of "standard form," but many textbooks define it this way:
The equation of a parabola whose axis of symmetry is parallel to the y axis is y = ax[sup:1jbx4mty]2[/sup:1jbx4mty] + bx + c
Your equation is this: y = (x - 1)(5x + 2)
Question: What would the right side look like if you DO the multiplication of (x - 1)(5x + 2)?
J
JeffM
Guest
sarahilc said:I'm having trouble with converting equations from vertex and factored form into standard... I just don't really get it.
How would I begin to rewrite this in standard form?:
y=(x-1)(5x+2)
One standard form for the parabola Is the quadratic so PERHAPS that is your answer. But perhaps the standard form you are supposed to find is
4p(y - k) = (x - h)[sup:3oitbkks]2[/sup:3oitbkks]. Is that what your question is?
Now there are formulas to give you h and k. Have you been taught them? Or are you confused about why the formulas work?
By the way if you are here because you do not understand why the formulas work, that shows that you are a wise student. If you memorize a formula without knowing why it works, you will never be sure when to use it or if you remembered it correctly.