If you mean "solve for precise values of x or y", you can't. If z= int(U), there are an infinite number of values of U that give the same z: any U satisfying \(\displaystyle z\le U< z+1\) (of course, z must be an integer- otherwise there is no solution). You could solve for an interval of values for y, say, by solving for y when x/(y*0.08+ x+ 99)= z and when x/(y*0.08+ x+ 99)= z+1. You could do the same to solve for x but that will be a little harder- it will be a quadratic equation.
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