Help With Distance Problem?

[Hanajima]

Set up an equation and solve the problem. (Objective 2)

On a 580-mile trip, Andy averaged 5 miles per hour faster for the last 124 miles than he did for the first 456 miles. The entire trip took 10 hours. How fast did he travel for the first 456 miles?

So I'm guessing we have the distance rate formula:

D= r x t

So we know that:

D=580miles
T= 10hrs

580= r x 10

I'm guessing that R will be (R[sub:3pw43pop]1[/sub:3pw43pop] + R[sub:3pw43pop]2[/sub:3pw43pop])?

R1= x/100 +5
R2= x/ 100

ehh..is that anywhere near correct? @.@
I couldn't find any problems in my math book similar to it and my teacher never gave any handouts with problems like that :?

 

[tkhunny]

R1= x/100 +5
R2= x/ 100

Not really following this. Where are 124 and 456?

 

[Hanajima]

R1= x/100 +5
R2= x/ 100

Not really following this. Where are 124 and 456?

I'm not exactly sure how to incorporate those two numbers in :?

Would I possibly have to set up two separate equations and solve?

Sorry, about this...I couldn't find a similar situation in previous problems my teacher showed us.

 

[tkhunny]

The are distances. One should go with R1 and the other with R2.

 

[Mrspi]

Set up an equation and solve the problem. (Objective 2)

On a 580-mile trip, Andy averaged 5 miles per hour faster for the last 124 miles than he did for the first 456 miles. The entire trip took 10 hours. How fast did he travel for the first 456 miles?

So I'm guessing we have the distance rate formula:

D= r x t

So we know that:

D=580miles
T= 10hrs

580= r x 10

I'm guessing that R will be (R[sub:25kzcwnt]1[/sub:25kzcwnt] + R[sub:25kzcwnt]2[/sub:25kzcwnt])?

R1= x/100 +5
R2= x/ 100

ehh..is that anywhere near correct? @.@
I couldn't find any problems in my math book similar to it and my teacher never gave any handouts with problems like that :?

You travel a TOTAL distance of 580 miles, but it is separated into two parts. One part is 456 miles, and the other part is 124 miles.

You WILL need the formula

distance = rate * time

You're asked to find the rate for the first 456 miles, so it seems a good idea to define your variable to represent that rate:

let x = rate for the first 456 miles
Now, we know that the rate for the last 124 miles of the trip was 5 mph faster than the rate for the first 456 miles.
Then x + 5 = rate for the last 124 miles

The total trip took 10 hours....would you agree with this?

time for first 456 miles + time for last 124 miles = total time

(456/x) + (124 / (x + 5)) = 10

There's your equation. Can you solve for x?

 

[Hanajima]

Set up an equation and solve the problem. (Objective 2)

On a 580-mile trip, Andy averaged 5 miles per hour faster for the last 124 miles than he did for the first 456 miles. The entire trip took 10 hours. How fast did he travel for the first 456 miles?

So I'm guessing we have the distance rate formula:

D= r x t

So we know that:

D=580miles
T= 10hrs

580= r x 10

I'm guessing that R will be (R[sub:1q0w5qbc]1[/sub:1q0w5qbc] + R[sub:1q0w5qbc]2[/sub:1q0w5qbc])?

R1= x/100 +5
R2= x/ 100

ehh..is that anywhere near correct? @.@
I couldn't find any problems in my math book similar to it and my teacher never gave any handouts with problems like that :?

You travel a TOTAL distance of 580 miles, but it is separated into two parts. One part is 456 miles, and the other part is 124 miles.

You WILL need the formula

distance = rate * time

You're asked to find the rate for the first 456 miles, so it seems a good idea to define your variable to represent that rate:

let x = rate for the first 456 miles
Now, we know that the rate for the last 124 miles of the trip was 5 mph faster than the rate for the first 456 miles.
Then x + 5 = rate for the last 124 miles

The total trip took 10 hours....would you agree with this?

time for first 456 miles + time for last 124 miles = total time

(456/x) + (124 / (x + 5)) = 10

There's your equation. Can you solve for x?

I got x=57, thank you for your help!