consider the function g(x)={sqrt(x^2+16) + x - 4 / x when x ≠ 0}
{ c when x = 0}
Determine what value of c, g(x) will be continuous at x = 0. Show your work.
okay so first, I tried to simplify the function by doing the limit as x approaches 0, and multiplying the top and bottom by sqrt(x^2+16) - x + 4.
Which then I get, (x^2+16) - x - 16 / x sqrt(x^2+16) - x + 4. By simplifying even more, I get = (x-1) / sqrt(x^2+16) - x + 4.
And now I am stuck. What do I do next??? Thank you in advance!!
{ c when x = 0}
Determine what value of c, g(x) will be continuous at x = 0. Show your work.
okay so first, I tried to simplify the function by doing the limit as x approaches 0, and multiplying the top and bottom by sqrt(x^2+16) - x + 4.
Which then I get, (x^2+16) - x - 16 / x sqrt(x^2+16) - x + 4. By simplifying even more, I get = (x-1) / sqrt(x^2+16) - x + 4.
And now I am stuck. What do I do next??? Thank you in advance!!