Help with applied problems

jconnors

New member
Joined
Oct 12, 2010
Messages
8
Here is the question;
Find three consecutive odd integers whose sum is 86 more than the second integer.

I have
I=1st
I+86=2nd
and I can't figure out the what 3rd should be. If I can get this then I can finish the problem.
Any help?
 
I have been looking at this for a minute now and I'm now at this;

I=1st
I+2=2nd
I+4=3rd

so then I come to this
I+I+4=86+I+2
However when I finish this out I don't think its correct.
Am I on the right path?
 
Hello, jconnors!

You're still misreding the problem . . .


Find three consecutive odd integers whose sum is 86 more than the second integer.

\(\displaystyle \text{Let: }\;\begin{Bmatrix}x &=& \text{1st odd integer} \\ x+2 &=& \text{2nd odd integer} \\ x+4 &=& \text{3rd odd integer} \end{Bmatrix}\)


\(\displaystyle \text{The equation is: }\;\underbrace{x + (x+2) + (x+4)}_{\text{Their sum}} \;\underbrace{=}_{\text{is}}\;\underbrace{86\;\;+}_{\text{86 more than}}\; \underbrace{(x+2)}_{\text{2nd integer}}\)

 
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