Help with a Linear System

finalfanatic

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Joined
Jan 27, 2012
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I have the following linear system:

3x + (3/2)y = -(1/2)
9x + 5y = 1

So far, I've done the following...
3x + (3/2)y = -(1/2) multiply by 6...
18x + 2y = = -3 multiply by -1...
-18x - 2y = 3

Then multiply the second equation by 2 to give...
18x + 10y = 1

Add both equations together to eliminate x giving
8y = 4
y = (1/2)

Subbing this back into the second equation
9x + 5(1/2) = 1
9x + (5/2) = 1

So we need to lose 3/2, so (3/2)/9 is 2/16 = 1/13

This means that x = -(1/13) and y = (1/2), is this correct or have I gone wrong somewhere?
 
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