help with 4 + 2/x / x/3 + 1/6, 2/t = t/5t-12

[brittany_micah]

Hi All!! My name is Brittany. This is my first time using this site. I am having a hard time with two problems. I'm completely confused and not quiet sure where to start. Thanks for your help!

4 + 2/x / x/3 + 1/6

I assume the top LCD is x and the bottom LCD is 6 and once I multiply those with the LCD's I flip the reciprical and multiple, but I'm not sure if this is right.

2/t = t/5t-12

I assume the LCD is 5t-12. But not sure what to do next

I know both of the answers to these problems, I'm just confused on what steps to take to get there.

 

[Deleted member 4993]

Re: Help w/ Problem

Hi All!! My name is Brittany. This is my first time using this site. I am having a hard time with two problems. I'm completely confused and not quiet sure where to start. Thanks for your help!

4 + 2/x / x/3 + 1/6

2/t = t/5t-12

First you got to tell us what the question is - for example did it say simplify, solve or what?

Then you got to write the questions properly - grouping with parenthesis.

Does your first one look like:

\(\displaystyle \frac{4 \, + \, \frac{2}{x}}{\frac{x}{3} \, + \frac{1}{6}}\)

if it is then you should have written as follows:

{4 + (2/x)}/{(x/3) + (1/6)}

\(\displaystyle \frac{2}{t} \, = \frac{t}{5t \, - \, 12}\)

if it is then you should have written as:

2/t = t/(5t - 12)

first of all tell us - the correct form of the problem - clearly indicating what you are supposed to do (solve, simplify, etc.)

Then share with us your work/thoughts, indicating exactly where you are stuck - so that we know where to begin to help you.

 

[brittany_micah]

Re: Help w/ Problem

The instructions say

Simplify:

{4 + (2/x)}/{(x/3) + (1/6)}


Solve the equation:

2/t = t/(5t - 12)

I know to find a LCD first and then to multiply the LCD with the numerators. So, for the first problem I think the LCD on the top is x and on the bottom is 6. I guess if I saw how to do each step on both problems. If you could walk me through each individual step I would understand it and be able to work more problems like this. I have referred to my text book and not had any luck. Thank You (and sorry it was in the wrong form to begin with)

 

[Deleted member 4993]

Re: Help w/ Problem

How would you evaluate (without calculator):

\(\displaystyle 4 \, + \, \frac{2}{5}\)

and

\(\displaystyle \frac{5}{3} \, + \, \frac{1}{6}\)

Please write out each step - it is important.

 

[Deleted member 4993]

Re: Help w/ Problem

How would you evaluate (without calculator):

\(\displaystyle 4 \, + \, \frac{2}{5}\)

and

\(\displaystyle \frac{5}{3} \, + \, \frac{1}{6}\)

Leave the answers of each problem as single fractions. Please write out each step - it is important.

 

[mmm4444bot]

Re: Help w/ Problem

... I know to find a LCD first and then to multiply the LCD with the numerators ...

We multiply an LCD times both the numerator and the denominator to obtain an equivalent fraction in preparation to combine it with another fraction. Is this what you are trying to say? We cannot simply multiply the numerator only because that would change the value of the fraction.

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... for the first problem I think the LCD on the top is x and on the bottom is 6. I guess if I saw how to do each step on both problems.

This "guess" is not a complete sentence, and your employment of the noun "problems" is ambiguous; therefore, I'm again unsure of what it is that you are trying to say.

If you already know that you are supposed to multiply, then what is preventing you from doing so? Are you afraid of making a mistake?

People learn mathematics by making mistakes.

-

... If you could walk me through each individual step I would understand it and be able to work more problems like this.

I'm not sure that either of these two predictions are true.

Please show us your steps, instead. We will then be able to see what you are doing; this in turn will allow us to understand where your difficulties lie.

If you are unable to add 4 and 2/x by using the LCD x, then please explain why you're stuck. If you are not able to explain this roadblock for us, then please proceed to show us your work completing the arithmetic that Subhotosh requested above, so that we may determine whether or not your roadblock is due to an inability to work with fractions in general.

We do not provide classroom lessons at this web site.

If you would like to see a beginning lesson on fractions, then click here.

If you would like to see a specific lesson on how to complete the arithmetic posted by Subhotosh, then click here.

Cheers,

~ Mark



"Spoon feeding in the long run teaches us nothing but the shape of the spoon." ~ E. M. Forster