Help w/ calculating measures of comp. angles w/ variables

L

LKMangrum

New member
Joined
Sep 10, 2007
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How do you calculate the measure of complementary and supplementary angles with variables?

GEOMETRY = UGH.
 
Please post an exact problem. We cannot guess at what you are talking about. Thank you.
 
I know you can't guess what I'm talking about. However, I have no way of drawing angles in my posting. So, I'll just try and explain one.

There are two intersecting lines, forming an X-like design. The top and bottom portions are obtuse angles, and the sides are acute. The top angle's measure is equal to 2x+12y. The bottom angle's measure is equal to 8y-4x. The right side's angle measure is equal to x+2y.

I appreciate you guys trying to help. Thanks.

:)
 
anglesnq6.gif

Is that the correct diagram?
You can post drawing as well.
Go to the top of this page to Forum Help.
On that tab you will see a link to inserting images.
 
Yes, that's the correct diagram, except that the angle on the right should say x+2y. Thanks so much. I'm new at this, so I'm still learning how to use it.
 
What is the definition of "supplementary" angles? What does the definition say about their angle sums?

What is the definition of "vertical" angles? What does the definition say about their angle measures?

What is the sum of any two angles which "add" to a straight line?

Use the answers to the above questions to set up the necessary equations and solve for x and y. (You haven't posted the actual question -- what you're supposed to do -- yet, so I'll guess that you have to solve for x and y, rather than finding the measures of the angles. But once you have x and y, finding the measures is simple.)

Eliz.
 
Oh sorry, yes, I have to find the values of x and y in order to find the measures of the angles.

I got up to the point where I found that 3x+14y=180.

I'm confused about what to do now.
 
\(\displaystyle \begin{array}{l}
2x + 12y = 8y - 4x,\mbox{ vertical angles} \\
\left( {2x + 12y} \right) + \left( {x + 2y} \right) = 180\mbox{ supplementary angles} \\
\end{array}\).

Now you solve that system.
 
LKMangrum said:
What system?
Click to expand...
You appear to need far more help than you can expect to get online.
Please have a sit-down with your instrtuctor.
 
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