Convert Y=(3/4)*x^(2/3) + (1-x^2)^(1/2) to parametric equation. Please help me this! Thank you!
C calculus1987 New member Joined Apr 8, 2013 Messages 1 Apr 8, 2013 #1 Convert Y=(3/4)*x^(2/3) + (1-x^2)^(1/2) to parametric equation. Please help me this! Thank you!
stapel Super Moderator Staff member Joined Feb 4, 2004 Messages 16,582 Apr 8, 2013 #2 calculus1987 said: Convert Y=(3/4)*x^(2/3) + (1-x^2)^(1/2) to parametric equation. Click to expand... Are you given any direction on what sort of parameters you're supposed to be using?
calculus1987 said: Convert Y=(3/4)*x^(2/3) + (1-x^2)^(1/2) to parametric equation. Click to expand... Are you given any direction on what sort of parameters you're supposed to be using?
H HallsofIvy Elite Member Joined Jan 27, 2012 Messages 7,763 Apr 9, 2013 #3 The easy answer: x= t y= (3/4)t^{2/3}+ (1- t^2)^{1/2} A slightly more complicated answer: x= sin(t) y= (3/4)sin^{2/3}(t)+ cos(t)
The easy answer: x= t y= (3/4)t^{2/3}+ (1- t^2)^{1/2} A slightly more complicated answer: x= sin(t) y= (3/4)sin^{2/3}(t)+ cos(t)