Help Solving Exponential Equation

jack_r12

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Could someone help me solve the equation, (18^2x)(3^-2x)=6
I'm assuming I'll use logs somewhere in that equation
 
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Could someone help me solve the equation, (18^2x)(3^-2x)=6
I'm assuming I'll use logs somewhere in that equation

To begin, let's rewrite the equation as follows:

\(\displaystyle \displaystyle \frac{18^{2x}}{3^{2x}}=6\)

Now, applying the rule for exponents \(\displaystyle \displaystyle \frac{a^{c}}{b^{c}}=\left(\frac{a}{b}\right)^c\), what do you get?
 
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