Help! plz

hobdenas

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Sep 25, 2005
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The perimiter of a rectangle is 14.9 m. if the length is 1.9m longer than the width, what are the dimentions of the rectangle?
 
2l+2w= 14.9 w is width l is length
but l=1.9+w substitute
2[1.9+w+w]=14.9
3.8 +4w= 14.9
4w= 11.1
w=11.1/4
Arthur
 
hobdenas said:
The perimiter of a rectangle is 14.9 m. if the length is 1.9m longer than the width, what are the dimentions of the rectangle?

Perimeter is the total distance around the rectangle.

Let x be the width
that would make the length x + 1.9

Can you take it from there?
 
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