Help Please

[elcatracho]

Hello.. I've been trying to figure out a problem that has been driving me nuts all night can someone please help me! I'm doing this problem by hand and I will show the steps that I've done so far. The problem is The definite Integral of (x^3+ absoulte value of the cos(x)) Evaluated on the interval of -pi to pi So Far I have split the two up and i found that the integral of x^3 equals zero because it's on the interval of -pi to pi. But the absolute value of cos(x) i have no idea what to do to evalute that. Can someone show me step by step how this is done. Thanks

 

[galactus]

If you notice the graph, as compared to 'regular' cosine, it lies only on the

positive y-axis. You could integrate \(\displaystyle \L\\2\int_{\frac{{-\pi}}{2}}^

{\frac{\pi}{2}}{x^{3}+(cos(x))}dx\) to get the same thing.

Just a thought.