Help please

[Guest]

Write an equation of the line that passes through the point (3,0) and is parallel to the line 2x+6y=-5

My book says the answer is y=-1/3x + 1

This is what I did:

6y=2x+-5

6y = 2x + -5
___ ___ ____
6 6 6

y=1/3x+-5/6


what am I doing wrong??????? Thanks so much.

 

[stapel]

How did you move "2x" to the other side of the equation without changing its sign?

Eliz.

 

[Denis]

Write an equation of the line that passes through the point (3,0) and is parallel to the line 2x+6y=-5
My book says the answer is y=-1/3x + 1
This is what I did:
6y=2x+-5
6y = 2x + -5
___ ___ ____
6 6 6
y=1/3x+-5/6
what am I doing wrong??????? Thanks so much.

I don't follow what "you did"; we have:
2x + 6y = -5 ; then:
6y = -2x - 5
y = (-2/6)x - 5/6
y = (-1/3)x - 5/6

so slope of new line is -1/3 (since parallel); you ok now?

 

[ChaoticLlama]

Standard equation of a line is

y = mx + b

where m is slope, b is the y intercept, and y and x are coordinates.

Find the slope of this line: 2x+6y=-5 by putting it into the standard form

2x + 6y = - 5

6y = -2x - 5

y = -1/3x - 5/6

so m = -1/3

and it gives a point on the line, (0,3)

So it looks as if you have the slope, and a point, plug those into the standard equation and solve for the y-int

 

[Denis]

Gee, manny, you got 3 replies in 3 minutes: 3.35, 3.36 and 3.37 !
...at FreeMath's, we do it all for you...

 

[Guest]

Thanks

Looks like I was on the right start. I appreciate everybodys help.