Re: HELP ON THIS PROBLEM PLEASE!
Hello, cole92!
Jeffrey visits his friend Kelly and then returns home by the same route.
He always bikes at 6mph when going uphill, 12 mph going downhill, and 8 mph on level ground.
Find the total distance he bikes if the total biking time is 6 hours.
To Kelly's house:
Let
U = number of uphill miles.
At 6 mph, his time uphill is:
6U hours.
Let
D = number of downhill miles.
At 12 mph, his downhill time is:
12D hours.
Let
L = number of level miles.
At 8 mph, his level time is:
8L hours.
His total time to Kelly's house is: \(\displaystyle \L\,\frac{U}{6}\,+\,\frac{D}{12}\,+\,\frac{L}{8}\,\) hours.
Return trip:
He bikes
D miles uphill at 6 mph; his uphill time is:
6D hours.
He bikes
U miles downhill at 12 mph; his downhill time is:
12U hours.
He bikes
L level miles at 8 mph; his level time is:
8L hours.
His total time for the return trip is: \(\displaystyle \L\,\frac{D}{6}\,+\,\frac{U}{12}\,+\,\frac{L}{8}\,\) hours.
The total time for the round trip is 6 hours:
\(\displaystyle \L\;\;\left(\frac{U}{6}\,+\,\frac{D}{12}\,+\,\frac{L}{8}\right)\,+\,\left(\frac{D}{6}\,+\,\frac{U}{12}\,+\,\frac{L}{8}\right)\;= \;6\;\;\Rightarrow\;\;\frac{U}{4}\,+\,\frac{D}{4}\,+\,\frac{L}{4}\;=\;6\)
Hence: \(\displaystyle \L\;U\,+\,D\.+\,L\;=\;24\) . . . He bikes 24 miles one way.
Therefore, his total distance is 48 miles.