Help please on exponential log problem

[Materia]

I'm having trouble getting started on these two log problems. Any little bit of help is appreciated.

Problem 1: log4(x+3) + log4(x-3) = 2

Problem 2: log3^x - log3^4 = 2

 

[galactus]

For #1

law of logs:

\(\displaystyle \L\\log_{4}(x+3)+log_{4}(x-3)=log_{4}((x-3)(x+3))\)

So, you have:

\(\displaystyle \L\\log_{4}((x+3)(x-3))=2\)

Another log law;

\(\displaystyle \L\\(x+3)(x-3)=4^{2}=16\)

Solve for x.