HELP!!!!! Part 2

meshun01

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Feb 11, 2006
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11
Let f(x) =x^3 -9x. Calulate the difference quotient f(3+h)-f(3)/h for

h=.1 ___________
h=.01 ___________
h=-.01 __________
h=-.1 ___________
 
((3+h)39(3+h))(339(3))h\displaystyle \frac{((3+h)^{3}-9(3+h))-(3^{3}-9(3))}{h}

=(h+3)(h+6)\displaystyle =(h+3)(h+6)
 
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