serenaleesl
New member
- Joined
- Oct 2, 2008
- Messages
- 6
Prove that lim(x->2) (1/x)= 1/2.?
why is the delta set at (1,2*epsilon)..i thought it's supposed to be (1,6*epsilon)?the steps are as follows:-
|1/x - 1/2| = |x-2|*1/2|x|
=1/2|x-2| (why do they eliminate x in this step?)
<1/2 delta
= epsilon..
i dont understand..
why is the delta set at (1,2*epsilon)..i thought it's supposed to be (1,6*epsilon)?the steps are as follows:-
|1/x - 1/2| = |x-2|*1/2|x|
=1/2|x-2| (why do they eliminate x in this step?)
<1/2 delta
= epsilon..
i dont understand..