find dy/dx if x=tan(x+y)
skeeter Elite Member Joined Dec 15, 2005 Messages 3,216 Jan 8, 2006 #2 \(\displaystyle d/dx[x = tan(x+y)]\) \(\displaystyle 1 = sec^2(x+y)(1 + dy/dx)\) \(\displaystyle 1 = sec^2(x+y) + sec^2(x+y)*(dy/dx)\) can you finish?
\(\displaystyle d/dx[x = tan(x+y)]\) \(\displaystyle 1 = sec^2(x+y)(1 + dy/dx)\) \(\displaystyle 1 = sec^2(x+y) + sec^2(x+y)*(dy/dx)\) can you finish?
