Help on a log problem

[iamtrojan5]

how would u solve for I?
75=10log(I/Io)
I already know Io, its a physics problem... its been a while since i've done logs.
Thanks alot

 

[skeeter]

75 = 10log(I/Io)

7.5 = log(I/Io)

10^7.5 = I/Io

Io*10^7.5 = I

 

[iamtrojan5]

wow thx for the reply skeeter =D