Help on a calculus question of evaluating the limits

theking

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evaluate
o2-o2A9VsujrEcBcro3HGz_Hnwoh75oNYX53i3jYGsSIc-kl6dMjYxJNyTc3ncnwDcFJSv47wvTHTpP4HEWYYW3eFyFzJxqGgsBa2rgtv4p6au21IJMZMpFuroAzMz6KBE4zzTU
 
im really confused about how to start this problem. Thx so much for helping me
 
If you haven't you learned L'Hospital's method, then use your knowledge of how the difference of cubes factors.
 
If you haven't you learned L'Hospital's method, then use your knowledge of how the difference of cubes factors.
The only thing i can think of right now it's i can let the cube root be a letter. but I don't know what to do next
 
While thinking about factoring a difference fo cubes, you may wish to think that you already have the two-term factor. Build the related three-term factor.
 
The only thing i can think of right now it's i can let the cube root be a letter. but I don't know what to do next
\(\displaystyle \left( {\frac{{\sqrt[3]{{1 + {\pi ^2}x}}-1}}{x}} \right)\left( {\frac{{{{(\sqrt[3]{{1 + {\pi ^2}x}})}^2} - (\sqrt[3]{{1 + {\pi ^2}x}}) + 1}}{{\sqrt[3]{{1 + {\pi ^2}x}}{)^2} - (\sqrt[3]{{1 + {\pi ^2}x}}) + 1}}} \right) = \frac{{1 + {\pi ^2}x - 1}}{{x\left( {\sqrt[3]{{1 + {\pi ^2}x}}{)^2} - (\sqrt[3]{{1 + {\pi ^2}x}}) + 1} \right)}}\)
 
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\(\displaystyle \left( {\frac{{\sqrt[3]{{1 + {\pi ^2}x}}}}{x}} \right)\left( {\frac{{{{(\sqrt[3]{{1 + {\pi ^2}x}})}^2} - (\sqrt[3]{{1 + {\pi ^2}x}}) + 1}}{{\sqrt[3]{{1 + {\pi ^2}x}}{)^2} - (\sqrt[3]{{1 + {\pi ^2}x}}) + 1}}} \right) = \frac{{1 + {\pi ^2}x - 1}}{{x\left( {\sqrt[3]{{1 + {\pi ^2}x}}{)^2} - (\sqrt[3]{{1 + {\pi ^2}x}}) + 1} \right)}}\)
how do i get rid of -1 in the numerator in the original formula?
 
how do i get rid of -1 in the numerator in the original formula?

The solution provided by pka (#9) had a small typo. However,if you work with paper and pencil and follow the general guideline provided by him (and in earlier responses), you should be able to get there easily!!
 
The only method I can think of is L hoptals rule. All you do is take the derivative of the top and bottom and then try taking the limit.
 
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