Help needed!

[julieDale-Jensen]

can anyone help me with the below problem:

A water tank is the shape of a rectangle, the base of the tank is 2m by 3m. Water is poured into the tank at a rate of 30litres per second. What is the rate of change of the depth of the water?

 

[nasi112]

Let [MATH]V[/MATH] be the volume and [MATH]h[/MATH] be the height of water, then

[MATH]V = 6h[/MATH]
Take the derivative of both sides with respect to time.
What do you get?

 

[lex]

Find out what height the water rises every second!
The volume of water added each second is [MATH]30000\text{cm}^3[/MATH]. This is the volume of a cuboid of water with the area of its base being [MATH]200\text{cm} \times300 \text{cm}=60000\text{cm}^2[/MATH]Divide the volume of water by the area of the base, to find out the height (that the water is rising every second).

 

[Deleted member 4993]

Let [MATH]V[/MATH] be the volume and [MATH]h[/MATH] be the height of water, then

[MATH]V = 6h[/MATH]
Take the derivative of both sides with respect to time.
What do you get?

While working with the equation about - be careful about the units. Remember

1 liter = 1000 cm³