lenkskendi
New member
- Joined
- Apr 13, 2023
- Messages
- 3
We'd be glad to help!Could you help me with this polynomial multiplication exercise?
(23x5+0x4+0x3+5x2−32x−15)⋅(2x3+54x2)
I've made the corrections. Thank you!The zeros are the coefficients of the x-terms, so the exponents need to be shown operating on the variables.
Also, the multiplication dot is optional.
(23x5 + 0x4 + 0x3 + 5x2 − 32x − 15)(2x3 + 54x2)