can someone help me.... g = .067 + .052 log (m)
T tommy New member Joined Oct 26, 2005 Messages 1 Oct 26, 2005 #1 can someone help me.... g = .067 + .052 log (m)
E Euler Junior Member Joined Jun 28, 2005 Messages 102 Oct 26, 2005 #2 This equation can have any number of solutions. Is there another equation that goes with it, so that you can use substitution?
This equation can have any number of solutions. Is there another equation that goes with it, so that you can use substitution?
S soroban Elite Member Joined Jan 28, 2005 Messages 5,586 Oct 27, 2005 #3 Hello, tommy! can someone help me.... g = .067 + .052 log (m) Click to expand... Sure, I'd be glad to help . . . but what is the question? Did they give us a value for m, and we're to evaluate g? Are we supposed to graph this equation? Are we supposed to solve for m? What??
Hello, tommy! can someone help me.... g = .067 + .052 log (m) Click to expand... Sure, I'd be glad to help . . . but what is the question? Did they give us a value for m, and we're to evaluate g? Are we supposed to graph this equation? Are we supposed to solve for m? What??
