Help me Please! Triangle question..is this possible?

needhelpoften!

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Feb 3, 2009
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The triangle ABC has vertices A(2,6) B(-10,1) and a 3rd vertex C which is one the line 5x-12y=18.?
Find the area of the triangle
 
The two given points determine a line. What is the slope of the line passing through the two points? What is the slope of the given line?
 
^ i've only been given this information....does have to do with something that they are paralell. im confused!
 
Draw two parallel lines. Pick out any two points on one of them. Pick any point on the other. Can you figure out what other information you need to find the area of the triangle formed by connecting the three points?
 
needhelpoften! said:
The triangle ABC has vertices A(2,6) B(-10,1) and a 3rd vertex C which is one the line 5x-12y=18.?
Find the area of the triangle
Please share with us your work, indicating exactly where you are stuck - so that we know where to begin to help you.
 
needhelpoften! said:
The triangle ABC has vertices A(2,6) B(-10,1) and a 3rd vertex C which is one the line 5x-12y=18.
Well, if you can't figure out that both lines AB and 5x - 12y = 18 have the same slope,
you're sure not ready to calculate the area of a triangle given the 3 vertices...

Question: what is the y-intercept of 5x - 12y = 18 ?
 
The triangle ABC has vertices A(2,6) B(-10,1) and a 3rd vertex C which is one the line 5x-12y=18.?
Find the area of the triangle

does have to do with something that they are parallel

A = (1/2)bh

The distance between the two points, A and B, is the base of the triangle.

The distance between the two parallel lines is the height of the triangle.

It does not matter where point C is on the line.
 
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