Help.. Logarithm Problem

[MathJason]

Hi everyone. I am answering CPT soon. The institute provides us with study material but it doesnt consist answers. So i would be really grateful if anyone of you help me solve the problems.

If logx= m+n
Logy = m-n
then log [(10x)/y^2)] =?????

a) 1-m+3n
b) m-1+3n
c) m+3n+1
d) None of these.
Please give me step bu step procedure to solve.

Ps: I do know the basics of logarithms.

 

[MathJason]

Please help me solve this Log problem

 

[Deleted member 4993]

Please help me solve this Log problem

The problem should have been (looking at the possible answers):

Given that log(x) = m + n and log(y) = m - n, the value of log[10x/y²] is expressed .....

Hint: log(p*q) = log(p) + log(q) and log(p^q) = q * log(p)

What are your thoughts?

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[MathJason]

Got it... Silly meeeeeee.

=log10 + logx - 2logy
=1+(m+n) - 2(m-n)
=1+m+n-2m+2n (I had always got it right uptil here. The mistake i made every single time was i multiplied 2 with -n instead of -2 with -n.) considering your hints i tried again, and this time i was careful enough to take care of minus sign).
Thanks a lot. I feel too silly now. Next time will come up with better problems.