Help! Last digit of billion digit number: 2^(3^(4^(5^(6^(7^(8^(9^10)))))))

[nonono]

how would you find the last digit of something like this mathematically? i am pretty sure i can translate the math into code, but i don't know how to do the math
eqn:
2^(3^(4^(5^(6^(7^(8^(9^10)))))))

 

[Deleted member 4993]

how would you find the last digit of something like this mathematically? i am pretty sure i can translate the math into code, but i don't know how to do the math
eqn:
2^(3^(4^(5^(6^(7^(8^(9^10)))))))

This is of the form 2ⁿ.

The last digit can be 2 or 4 or 6 or 8.

continue.....

 

[stapel]

how would you find the last digit of something like this mathematically? i am pretty sure i can translate the math into code, but i don't know how to do the math
eqn:
2^(3^(4^(5^(6^(7^(8^(9^10)))))))

What patterns have you found in ending ("ones") digits in the powers of 2?

Please be complete. Thank you!