Help in Integration/Differentiation question NEEDED!!

[NiCeBoY]

Hello,
i got one question, and i tried to answer it...

I am a bit lost.. but managed to do allmost all of it..
can anyone check out my answer and let me know if everything is right.. and if not please correct it for me..

thanks a lot..
the question and answer is attached..
thanks..
Question:
[attachment=21n8i18o]ques1.JPG[/attachment1n8i18o]

ANSWER PAGE 1:
[attachment=11n8i18o]rep1.JPG[/attachment1n8i18o]

ANSWER PAGE 2 :
[attachment=01n8i18o]rep12.JPG[/attachment1n8i18o]

Thanks.

 

[Deleted member 4993]

Hello,
i got one question, and i tried to answer it...

I am a bit lost.. but managed to do allmost all of it..
can anyone check out my answer and let me know if everything is right.. and if not please correct it for me..

thanks a lot..
the question and answer is attached..
thanks..
Question:
[attachment=2:1fokqjv1]ques1.JPG[/attachment:1fokqjv1]

ANSWER PAGE 1:
[attachment=1:1fokqjv1]rep1.JPG[/attachment:1fokqjv1]

ANSWER PAGE 2 :
[attachment=0:1fokqjv1]rep12.JPG[/attachment:1fokqjv1]

Thanks.

parts (a) and (b) looks good - except why did you start using 'k' in part (b)? Keep 'R' in there - just for clarity.

What about part (c)? It is fairly simple - straight forward "evaluation".

 

[BigGlenntheHeavy]

Good Show, Niceboy, as Subhotosh Klan said, everthing is correct, as I also worked out this problem.

A good exercise.

 

[NiCeBoY]

[attachment=0:2ud6iemn]ques1.JPG[/attachment:2ud6iemn]

Yes but how do i find the Value of "K" to proceeed for part (C) please?

Can anyone help me out to complete it..
thanks

 

[Deleted member 4993]

Did you read my response - carefully....

 

[NiCeBoY]

yeah bro,
i did read it crefully..
i did use K because in part "b" its using K...

so if i change it back to R..
i can use the value of R to substitute in the equation?
am i right?

thanks

 

[Deleted member 4993]

yeah bro,
i did read it crefully..
i did use K because in part "b" its using K...

so if i change it back to R..
i can use the value of R to substitute in the equation?
am i right?

thanks

Now you tell me BRO...

when you switched from 'R' to 'k' - what relation ship did you use? Use the "inverse" of that relationship. That is

if you used square (x[sup:wubdhw2k]2[/sup:wubdhw2k]) relationship - now you'll use "square-root" relationship

if you used exponential (e[sup:wubdhw2k]x[/sup:wubdhw2k]) relationship - now you'll use "log[sub:wubdhw2k]e[/sub:wubdhw2k]" relationship

and so on.....

 

[NiCeBoY]

i think k = 50x10^-9 = R

 

[NiCeBoY]

am right or not?

 

[NiCeBoY]

oh yeah i got it...
i will comlete it and post the answer..
thx

 

[NiCeBoY]

Hello,
i hope this time the answer is perfect without any errors
[attachment=1:2zwbgyei]ans1.JPG[/attachment:2zwbgyei]
[attachment=0:2zwbgyei]ans12.JPG[/attachment:2zwbgyei]

thx

 

[Deleted member 4993]

Excellent work - exactly the way I would like to see - no scribbling, skipping lines - confident and clean writing. Again - excellent work....

 

[NiCeBoY]

thank you very much for your help though man...