[HELP] Implicit differentiation ( exponential form )
- Thread starter iankasai
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I would reduce your result to the first part as:
\(\displaystyle \displaystyle \frac{dy}{dx}=\frac{xe^{x^2}+6}{y}\)
Now differentiate again, using the quotient rule on the right, and your result from the first part. Can you post your attempt at this?
\(\displaystyle \displaystyle \frac{dy}{dx}=\frac{xe^{x^2}+6}{y}\)
Now differentiate again, using the quotient rule on the right, and your result from the first part. Can you post your attempt at this?
D
Deleted member 4993
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after doing the quotient rule. I don't know what to do next. Can u demonstrate it to me how to answer it?
After applying the quotient rule - you should have to simplify.
Please share your work with us so that we can provide you with more specific instructions.
D
Deleted member 4993
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Instead of using quotient rule, I would use implicit differentiation again:
\(\displaystyle y*y' = x*e^{x^2} + 6 \)
\(\displaystyle y*y" + (y')^2 = e^{x^2} + 2x^2 * e^{x^2}\)
and simplify....
\(\displaystyle y*y' = x*e^{x^2} + 6 \)
\(\displaystyle y*y" + (y')^2 = e^{x^2} + 2x^2 * e^{x^2}\)
and simplify....