Help--I would like to verify my answer

[Typaradise]

Any help is appreciated...

1. x*2=-400

sqrt x*2= sqrt 400
x=sqrt20i sqrt 2

Answer: x=+/- 2 sqrt 5i sqrt 2




2. 48-x*2=0

Answer: x+/- sqrt 48 x+-4 sqrt 3

 

[arthur ohlsten]

x^2=-400
x^2=[400 i^2]
x=+/- 20 i


sqrt 400= sqrt [2x200]
sqrt 400 = sqrt[ 2x2x100]
sqrt400=sqrt [2x2x 2x50]
sqrt400=sqrt[2x2x2x2x5x5]

sqrt400= +/- 2x2x5
sqrt 400 = +/- 20
then sqrt -400 = +/- 20i
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48-x^2=0
x^2=48
x^2=[2x2x2x2x3]
x=+/- 2x2xsqrt3
x= +/- 4 sqrt3

 

[Typaradise]

Thank you