help i have about an hour to figure this out

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grimlins88@yahoo.com

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HI I am working on page 605 out of Elementary and Intermediate Algebra I need to work “a”, “b”, and “c” of problem 103. I have the first two parts but am stuck on "c". This is the problem:
c)The accompanying graph shows C in terms of d for the Tartan 4100 (b = 13.5). For what displacement is the Tartan 4100 safe for ocean sailing? I think I would write it as c=54(d^(-1/3))13.5 but don't know where to go from here?
dug_09_4356_ch09_u024.png
thank you for any help you can provide.
 
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grimlins88@yahoo.com said:
HI I am working on page 605 out of Elementary and Intermediate Algebra I need to work “a”, “b”, and “c” of problem 103. I have the first two parts but am stuck on "c". This is the problem:
c)The accompanying graph shows C in terms of d for the Tartan 4100 (b = 13.5). For what displacement is the Tartan 4100 safe for ocean sailing? I think I would write it as c=54(d^(-1/3))13.5 but don't know where to go from here?
dug_09_4356_ch09_u024.png
thank you for any help you can provide.
Click to expand...
I have gotten (54b^(3/1))/c^(3/1) =d
 
grimlins88@yahoo.com said:
I came to the answer 54b^(3/1)=d
Click to expand...
It is hard to tell what you are doing and where you are going wrong if you give just an answer but no work. Furthermore you do not give the complete problem so we are guessing.

I am guessing that that C = capsize screening value and that a boat is considered safe if

\(\displaystyle C \le 2,\ where\ C = 54d^{-(1/3)}b = \dfrac{54b}{d^{(1/3)}} = \dfrac{54b}{\sqrt[3]{d}},\ d > 0,\ and\ b > 0.\)

\(\displaystyle So\ b = 13.5\ and\ C \le 2 \implies \dfrac{what?}{\sqrt[3]{d}} \le what?\)

Now here is a hint. Cube both sides of the inequality.

Does the direction of inequality change or not change? Why?
 
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