[Travel Speed (mph), Braking Distance (ft)]
[20(mph), 20 (ft)]
[40(mph), 105 (ft)]
[60(mph), 300(ft)]
a)Find a quadratic function that fits the data on the right.
b) Use the function to estimate the braking distance of a car that travels at 50 mph.
c) Does it make sense to use this function when speeds are less than 10 mph? Why or why not?
y=ax^2+bx+c
[20(mph), 20 (ft)] (20)=a(20)^2+b(20)+C = 20=400a+20b+C
[40(mph), 105 (ft)](105)=a(40)^2+b(40)+C = 105=1600a+40b+C
[60(mph), 300(ft)] (300)=a(60)^2+b(60)+C = 300=3600a+60b+C
Okay. I am stuck and I don't know how to work the rest of this problem. I been puzzle yet can't figure out what are the next following steps. I need some Dummy 101 instructions to solve this problem... that if anyone is able to help solve this problem.
Need to figure this out so I can prepare for my final!
[20(mph), 20 (ft)]
[40(mph), 105 (ft)]
[60(mph), 300(ft)]
a)Find a quadratic function that fits the data on the right.
b) Use the function to estimate the braking distance of a car that travels at 50 mph.
c) Does it make sense to use this function when speeds are less than 10 mph? Why or why not?
y=ax^2+bx+c
[20(mph), 20 (ft)] (20)=a(20)^2+b(20)+C = 20=400a+20b+C
[40(mph), 105 (ft)](105)=a(40)^2+b(40)+C = 105=1600a+40b+C
[60(mph), 300(ft)] (300)=a(60)^2+b(60)+C = 300=3600a+60b+C
Okay. I am stuck and I don't know how to work the rest of this problem. I been puzzle yet can't figure out what are the next following steps. I need some Dummy 101 instructions to solve this problem... that if anyone is able to help solve this problem.
Need to figure this out so I can prepare for my final!