Help from experts w/ -8t -11t = -19, etc.

skyemonae2

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Jun 16, 2007
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I need some assistence on a couple of problems-just want to see if I'm on the right track.

1) -4(-4 to the 2nd + 1-5u to the third)

2) -8t -11t = -19

3) 1/3x + 1/2= 2/5

would appreciate any help

thanks
 
Hello, skyemonae2!

I need some assistance on a couple of problems-just want to see if I'm on the right track.

Alright I'll show you the processes but not the answers.

\(\displaystyle \L \;-\,4(\,-\,4^{2}\,+\,1\,-\,5u^3)\)

First simplify the \(\displaystyle \,-\,4^2\,\) to -16. Then Distribute the -4, or take -4 times all the terms inside the parenthesis.

So you have: \(\displaystyle \L \;\,-\,4\,\cdot\,-\,16\,+\,\,-\,4\,\cdot\,1\,+\,-\,4\,\cdot\,-\,5u^3\)

If you are confused on that, check on Distributive Property/Distributive Property of Multiplication over Addition.

\(\displaystyle \L \;\,-\,8t\,-\,11t\,=\,-\,19\)

Combine like terms on the left side of the equal sign: \(\displaystyle \L \;-\,19t\,=\,-\,19\)

So what does \(\displaystyle t\) have to be?

\(\displaystyle \L \;\frac{1}{3}x\,+\,\frac{1}{2}\,=\,\frac{2}{5}\)

Subtract \(\displaystyle \frac{1}{2}\) from both sides of the equation: \(\displaystyle \L \;\frac{1}{3}x\,=\,-\,\frac{1}{10}\)

So what does \(\displaystyle x\) equal?

There you go!
 
Re: Help from experts

skyemonae2 said:
I need some assistence on a couple of problems-just want to see if I'm on the right track.
thanks

To see whether you are on the right track or not - we need to see the tracks created by you.

How about showing your work - so that we can help you properly!
 
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